13 April 2014

CBSE Physics Numerical based on chapter - Electricity & its effects For (Class X)


NUMERICAL - Electricity and its effects For (Class X)

1. A resistance of 6 ohms is connected in series with another resistance of 4 ohms. A potential difference of 20 volts is applied across the combination. Calculate the current through the circuit and potential difference across the 6 ohm  resistance.
2. Calculate the number of electrons constituting one coulomb of charge per second through any cross section of a conductor.
3. How much work is done in moving a charge of 2 C across two points having a potential difference of 12 V ?
4. How much energy is given to each coulomb of charge passing through a 6 V battery ?
5. Calculate the work done in moving a charge of 5 Coulombs from a point at a potential of 210 Volts to another point at 240 Volts.
7. When a particle of charge 10 µC is brought from infinity to a point P, 2.0 mJ work is done by the external forces. What is the potential at P ?
9. How many electrons pass through a lamp in one minute if the current be 200 mA?
10. Calculate the current supplied by a cell if the amount of charge passing through the cell in 4 seconds is 12 C ?
11. A 2 Volt cell is connected to a 1 Ω resistor. How many electrons come out of the negative terminal of the cell in 2 minutes?
12. a)  How much current will an electric bulb draw from a 220 V source, if the resistance of the bulb filament is 1200 Ω ?
b)  How much current will an electric heater coil draw from a 220 V source, if the resistance of the heater coil is 100 Ω ?
13. The potential difference between the terminals of an electric heater is 60 Volts when it draws a current of 4 Ampere from a source. What current will the heater draw if the potential difference is increased to 120 Volt.  
14. A torch bulb when cold has 1Ω resistance. It draws a current of 0.3 Ampere when glowing from a source of 3 V. Calculate the resistance of the bulb when glowing and explain the reason for the difference in resistance.   

2 comments:

J Sunil said...

1.Calculate the current and resistance of a 100 W ,200V electric bulb.
Solution:
Power,P = 100W
Voltage,V = 200V
Power p = VI
Current I = P = 100 = 0.5A
V 200
Resistance R = V = 200 = 400W.
I 0.5
2. Calculate the power rating of the heater coil when used on 220V supply taking 5 Amps.
Solution:
Voltage ,V = 220V
Current ,I = 5A,
Power,P = VI = 220 × 5
= 1100W = 1.1 KW.
3.A circuit is made of 0.4 Ω wire,a 150Ω bulb and a 120Ω rheostat connected in series.Determine the total resistance of the resistance of the circuit.
Solution:
Resistance of the wire = 0.4Ω
Resistance of bulb = 150Ω
Resistance of rheostat = 120Ω
In series,
Total resistance ,R = 0.4 + 150 +120
= 270.4Ω
4.In the circuit shown in fig .find the current,voltage drop across each resistor and the power dissipated in each resistor.

Total resistance of the circuit = 2 + 6 +7
R = 15 Ω
Voltage ,V = 4 5V
Circuit current ,I = V = 45 = 3A
R 15
Voltage drop across 2Ω resistor V1 = I R1
= 3 × 2 = 6 Volts.
Voltage drop across 6Ω resistor V2 = I R2
= 3 × 6 = 18 volts.
Voltage drop across 7Ω resistor V3 = I R3
= 3 × 7 = 21 volts.
Power dissipated in R1 is P1 = P R1
= 32 × 2 = 18 watts.
Power dissipated in R2 is P2 = I2 R2.
= 32 × 6 = 54 watts.
Power dissipated in R3 is P3 = I2 R3.
= 32 × 7 = 63 watts.

Yashraj Dhongani said...

Can I get the answers for the questions above

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