26 October 2012

Floatation: Previous Year s’ Questions of 3 marks for class IX

1. An object is made to fall from different heights 20 cm, 40 cm and 60 cm on wet sand.
 (a) What do you observe on the sand?  (b) Explain the reasons of the observations. CBSE Questions

2. A solid object of mass 50 g and volume 100 cm3 is put in water. Will the object float or sink? Give reasons for your answer.

3. Name the instrument used to determine the density of liquid in which balance and graduated cylinder are not required. Why this instrument is made heavy near the bottom?

4. A sphere of mass 5 kg and volume 2.2 × 10–4 m3 is completely immersed in water. Find the buoyant force exerted by water on the sphere. Density of water = 1000 kgm–3. (Given: g =9.8m/s2)

5. What happens when :(a) Buoyant Force exerted by the fluid is less than the weight of the body?
(b) Buoyant Force exerted by the fluid is equal to the weight of the body?

6. What is Relative Density? The relative density of a substance is greater than 1, w hat does it signify?

7. If relative density of aluminum is 2.7 and density of water is 1000 kg/m3. What is the density of aluminum in SI unit?

8. The volume of a solid block is 300 cm3, find the mass of water displaced when it is immersed in water? (Density of water is 1 g/cm3)

9. (a) A floating boat displaces water weighing 6000 N.
(i) What is the buoyant force on the boat?  (ii) What is the weight of boat?
(b) What happens to the buoyant force as more and more volume of a solid object is immersed in a liquid?

10. (a) Define relative density.

(b) Relative density of gold is 19.3. The density of water is 10.3 kg/m3. What is the density of gold in S.I. units?
More Questions are solved Here:  Floatation Thrust-and-pressure

IX Thrust and Pressure, Archimedes’ Principle, Relative Density
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6 comments:

  1. Q. An object is made to fall from different heights 20 cm, 40 cm and 60 cm on a wet sand.
    (a) What do you observe on the sand?
    (b) Explain the reasons of the observations. [2011 (T-II)]
    Ans. (a) These ojects create depressions in the wet sand. The largest depression is created by the
    object falling from largest height i.e. 60 cm and the smallest depression by the object
    falling from lowest height i.e., 20 cm.
    (b) It is because on falling through a greater height, the object has more velocity and thus
    having more kinetic energy.

    ReplyDelete
  2. Q. Name the instrument used to determine the density of liquid in which balance and graduated cylinder are not required. Why this instrument is made heavy near the bottom?
    Ans: The instrument used to determine the density of liquids is hydrometer. It consists of a uniform test tube. The base of the tube is made heavier by taking few lead shots in it so that the tube remains vertical while floating in water or a given liquid.

    ReplyDelete
  3. Questions : Loaded test-tube placed in pure milk sinks to a certain mark (M). Now some water is mixed with the milk. Will the test tube sink more or less? Explain. [2011 (T-II)]

    Ans. As density of milk is greater than density of water, so when some water is mixed with milk,
    then amount of buoyant force is decreased at some extent. Consequently test tube will sink
    more.

    ReplyDelete
  4. Q. If relative density of aluminium is 2.7 and density of water is 1000 kg/m3. What is the density of aluminium in SI unit? [2011 (T-II)]
    Ans. Relative density of aluminium = Density of aluminium/Density of water
    ⇒ Density of aluminium = Relative density of aluminium × Density of water
    = 2.7 × 1000 kg /m3 = 2700 kg/m3

    ReplyDelete
  5. Q. A sphere of mass 5 kg and volume 2.2 × 10–4 m3 is completely immersed in water. Find the buoyant force exerted by water on the sphere. Density of water = 1000 kgm–3 (Given : g = 9.8 ms–2). [2011 (T-II)]
    Ans. Here, volume of sphere = Volume of water displaced = 2.2 × 10–4 m3
    (∵ sphere is completely immersed in water)
    Mass of the water displaced = Volume × Density = 2.2 × 10–4m3 × 1000 kg m–3 = 2.2 × 10–1 kg
    Thus, buoyant force exerted by water = weight of water displaced = mg
    = 2.2 × 10–1 kg × 9.8 m/s2 = 21.56 × 10–1 N = 2.156 N

    ReplyDelete
  6. Any one can post answer of remaining question

    ReplyDelete

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